Question 1

Females who are "carriers" for hemophilia:

Accepted Answer

A)  Theoretically pass the allele for hemophilia to half of their offspring
B)  Theoretically pass the allele for hemophilia to half of their daughters who become at least "carriers" for this disorder
C)  All are correct
D)  Theoretically pass the allele for hemophilia to half of their sons who become hemophiliacs
E)  Usually do not show any symptoms of hemophiliaF) A) and E)
G) B) and C)

Question 2

A healthy young couple are both carriers of cystic fibrosis,the chance that each of their future children will inherit this serious illness is:

Accepted Answer

A)  0%, because cystic fibrosis is not an inherited illness
B)  25%
C)  10%
D)  50%
E)  100%F) B) and E)
G) A) and E)

Question 3

Figure 10.28 
-In Figure 10.28,the F1 generation shows mating of resistant bollworms (___) with susceptible heterozygous (____) bollworms.

Accepted Answer

A)  rr, Rr
B)  rr, RR
C)  RR, rr
D)  Rr, rr
E)  Rr, RRF) A) and B)
G) A) and E)

Question 4

If a genetic counselor was examining a pedigree chart and noticed an occurrence of a disease in every generation,he most likely could assume that the disease was caused by:

Accepted Answer

A)  A new reoccurring mutation
B)  An autosomal recessive disorder
C)  A chromosomal abnormality
D)  An autosomal dominant disorder
E)  Having an extra set of chromosomesF) None of the above
G) A) and D)

Question 5

In the ABO blood type system,there are six possible genotypes,but only two possible phenotypes.

Accepted Answer

A) True 
 B)False

Question 6

A sexual life cycle has three main events: meiosis,gamete formation,and fertilization.

Accepted Answer

A) True 
 B)False

Question 7

If you cross two pea plants,one with green peas and the other with yellow peas.All of the offspring have yellow peas.You conclude:

Accepted Answer

A)  The yellow parent was homozygous for the recessive allele
B)  The yellow parent was homozygous for the dominant gene
C)  The yellow parent was homozygous for the dominant allele
D)  The yellow parent was homozygous for the recessive gene
E)  The yellow parent was heterozygousF) A) and C)
G) None of the above

Question 8

If the heterozygous phenotype is intermediate between those of the two different homozygotes,this is called:

Accepted Answer

A)  Codominance
B)  Independent assortment
C)  Epistasis
D)  Incomplete dominance
E)  PolygenicF) B) and E)
G) B) and D)

Question 9

Figure 10.28 
-In Figure 10.28,the genotype of the resistant parental bollworms is ___ while the susceptible parental bollworms have a ___ genotype.

Accepted Answer

A)  rr, RR
B)  RR, rr
C)  Rr, rr
D)  RR, Rr
E)  Rr, RRF) C) and E)
G) A) and B)

Question 10

Alternate forms of the same gene are called:

Accepted Answer

A)  Chromatids
B)  Centromeres
C)  Chromosomes
D)  Alleles
E)  TraitsF) A) and B)
G) B) and E)

Question 11

The individual sometimes referred to as the "father of genetics" because he influenced the science of genetics more than anyone else is Gregor Mendel.

Accepted Answer

A) True 
 B)False

Question 12

In pedigree charts,autosomal dominant disorders typically:

Accepted Answer

A)  Appear only in males
B)  Appear only in females
C)  Appear in every generation
D)  Seem to disappear in one generation, only to reappear in the next generation
E)  Occur every third generationF) C) and E)
G) None of the above

Question 13

You mate two pea plants that are both AaBb and get a 3:1 phenotype ratio.This suggests:

Accepted Answer

A)  Independent assortment occurred
B)  Crossing over occurred
C)  Genes A and B are on different chromosomes
D)  Non-disjunction occurred
E)  Genes A and B are on the same chromosomeF) B) and D)
G) None of the above

Question 14

An allele that exerts its effects whenever it is present is:

Accepted Answer

A)  Recessive
B)  Dominant
C)  Homologous
D)  Homozygous
E)  HeterozygousF) A) and B)
G) B) and D)

Question 15

Hemophilia A is an X-linked recessive disorder.If a normal man marries a woman who is a carrier,what fraction of their sons will have hemophilia?

Accepted Answer

A)  50%
B)  25%
C)  0%
D)  100%
E)  75%F) C) and D)
G) C) and E)

Question 16

If you cross RrYy and RRyy pea plants,what fraction of the offspring will have round peas? R=round,r=wrinkled,Y=yellow,y=green.

Accepted Answer

A)  50%
B)  75%
C)  100%
D)  25%
E)  0%F) A) and D)
G) A) and C)

Question 17

If a diploid cell has 14 chromosomes,it will have:

Accepted Answer

A)  14 pairs of homologous chromosomes
B)  7 pairs of homologous chromatids
C)  14 pairs of homologous chromatids
D)  7 pairs of homologous chromosomes
E)  14 allelesF) B) and E)
G) A) and D)

Question 18

In a testcross,if all the offspring show the dominant phenotype,then the individual with the unknown genotype was:

Accepted Answer

A)  Heterozygous
B)  Homozygous dominant
C)  Homozygous recessive
D)  A clone of the other testcross individual
E)  Heterozygous recessiveF) A) and B)
G) B) and E)

Question 19

Autosomes are numbered according to:

Accepted Answer

A)  Size
B)  Location within the nucleus
C)  Centromere position
D)  Banding pattern
E)  The random location within the karyotypeF) B) and E)
G) All of the above

Question 20

In order for a girl to inherit hemophilia A,her parents would have which genotypes?

Accepted Answer

A)  XH XH, Xh Y
B)  XH Xh,XH Y
C)  XH XH,XH y
D)  XH Xh,Xh Y
E)  Xh Xh,XH yF) None of the above
G) A) and B)

Exam 10: Patterns of Inheritance

In pedigree charts,autosomal dominant disorders typically:

Correct AnswerverifiedShow Answer

If a genetic counselor was examining a pedigree chart and noticed an occurrence of a disease in every generation,he most likely could assume that the disease was caused by:

Correct AnswerverifiedShow Answer

Figure 10.28 -In Figure 10.28,the F1 generation shows mating of resistant bollworms (___) with susceptible heterozygous (____) bollworms.

Correct AnswerverifiedShow Answer

Hemophilia A is an X-linked recessive disorder.If a normal man marries a woman who is a carrier,what fraction of their sons will have hemophilia?

Correct AnswerverifiedShow Answer

If a diploid cell has 14 chromosomes,it will have:

Correct AnswerverifiedShow Answer

An allele that exerts its effects whenever it is present is:

Correct AnswerverifiedShow Answer

If you cross RrYy and RRyy pea plants,what fraction of the offspring will have round peas? R=round,r=wrinkled,Y=yellow,y=green.

Correct AnswerverifiedShow Answer

If you cross two pea plants,one with green peas and the other with yellow peas.All of the offspring have yellow peas.You conclude:

Correct AnswerverifiedShow Answer

Females who are "carriers" for hemophilia:

Correct AnswerverifiedShow Answer

Figure 10.28 -In Figure 10.28,the genotype of the resistant parental bollworms is ___ while the susceptible parental bollworms have a ___ genotype.

Correct AnswerverifiedShow Answer

Alternate forms of the same gene are called:

Correct AnswerverifiedShow Answer

You mate two pea plants that are both AaBb and get a 3:1 phenotype ratio.This suggests:

Correct AnswerverifiedShow Answer

If the heterozygous phenotype is intermediate between those of the two different homozygotes,this is called:

Correct AnswerverifiedShow Answer

Autosomes are numbered according to:

Correct AnswerverifiedShow Answer

In order for a girl to inherit hemophilia A,her parents would have which genotypes?

Correct AnswerverifiedShow Answer

The individual sometimes referred to as the "father of genetics" because he influenced the science of genetics more than anyone else is Gregor Mendel.

Correct AnswerverifiedShow Answer

A sexual life cycle has three main events: meiosis,gamete formation,and fertilization.

Correct AnswerverifiedShow Answer

In the ABO blood type system,there are six possible genotypes,but only two possible phenotypes.

Correct AnswerverifiedShow Answer

In a testcross,if all the offspring show the dominant phenotype,then the individual with the unknown genotype was:

Correct AnswerverifiedShow Answer

A healthy young couple are both carriers of cystic fibrosis,the chance that each of their future children will inherit this serious illness is:

Correct AnswerverifiedShow Answer

Correct Answer
verified

Correct Answer
verified

Figure 10.28 -In Figure 10.28,the F1 generation shows mating of resistant bollworms (_) with susceptible heterozygous (__) bollworms.

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Figure 10.28 -In Figure 10.28,the genotype of the resistant parental bollworms is _ while the susceptible parental bollworms have a _ genotype.

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified